On the solutions of the difference equation x(n+1)=x(n-1)/-1+ax(n)x(n-1)

Cinar, C2020-03-262020-03-2620040096-3003https://dx.doi.org/10.1016/j.amc.2003.08.139https://hdl.handle.net/20.500.12395/19150We investigate the solutions of the difference equation x(n+1) = x(n-1)/-1+ax(n)x(n-1), n = 0, 1, 2,..., where a > 0, x(-1) and x(0) are real numbers such that ax(-1)x(0) not equal 1. (C) 2003 Elsevier Inc. All rights reserved.en10.1016/j.amc.2003.08.139info:eu-repo/semantics/closedAccessdifference equationrecursive sequenceOn the solutions of the difference equation x(n+1)=x(n-1)/-1+ax(n)x(n-1)Article1583793797Q1WOS:000224707600013Q3