On the solutions of the differenceequation xn+1 =Axn-(2k+1)/ -A+2?+1p{cyrillic}i=0xn-i

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dc.contributor.authorKaratas C.
dc.contributor.authorYalcinkaya I.
dc.date.accessioned2020-03-26T18:22:18Z
dc.date.available2020-03-26T18:22:18Z
dc.date.issued2011
dc.departmentSelçuk Üniversitesien_US
dc.description.abstractIn this paper, we study the solutions of the difference equation xn+1 =Axn-(2k+1)/ -A+2?+1p{cyrillic}i=0xn-i for n=0, 1, 2, where ? is a positive number and initial conditions are non zero real numbers with p{cyrillic} 2k+1 i=0x-i?© 2011 by the Mathematical Association of Thailand. All rights reserved.en_US
dc.identifier.endpage126en_US
dc.identifier.issn1686-0209en_US
dc.identifier.issue1en_US
dc.identifier.scopusqualityQ4en_US
dc.identifier.startpage121en_US
dc.identifier.urihttps://hdl.handle.net/20.500.12395/27268
dc.identifier.volume9en_US
dc.indekslendigikaynakScopusen_US
dc.language.isoenen_US
dc.relation.ispartofThai Journal of Mathematicsen_US
dc.relation.publicationcategoryMakale - Uluslararası Hakemli Dergi - Kurum Öğretim Elemanıen_US
dc.rightsinfo:eu-repo/semantics/closedAccessen_US
dc.selcuk20240510_oaigen_US
dc.subjectDifference equationen_US
dc.subjectPeriodicityen_US
dc.subjectSolutionen_US
dc.titleOn the solutions of the differenceequation xn+1 =Axn-(2k+1)/ -A+2?+1p{cyrillic}i=0xn-ien_US
dc.typeArticleen_US

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