On the recursive sequence x(n+1) = xn-(5k+9)/1+xn-4xn-9 ... xn-(5k+4)
dc.contributor.author | Simsek, Dagistan | |
dc.contributor.author | Cinar, Cengiz | |
dc.contributor.author | Yalcinkaya, Ibrahim | |
dc.date.accessioned | 2020-03-26T17:27:22Z | |
dc.date.available | 2020-03-26T17:27:22Z | |
dc.date.issued | 2008 | |
dc.department | Selçuk Üniversitesi | en_US |
dc.description.abstract | In this paper a solution of the following difference equation was investigated x(n+1) = x(n-(5k+9))/1+x(n-4)x(n-9) ... x(n-(5k+4)), n =0, 1, 2, ... where x(-(5k+9)), x(-(5k+8)), ..., x(-1), x(0) is an element of (0, infinity). | en_US |
dc.identifier.endpage | 1099 | en_US |
dc.identifier.issn | 1027-5487 | en_US |
dc.identifier.issue | 5 | en_US |
dc.identifier.startpage | 1087 | en_US |
dc.identifier.uri | https://hdl.handle.net/20.500.12395/22545 | |
dc.identifier.volume | 12 | en_US |
dc.identifier.wos | WOS:000258111700006 | en_US |
dc.identifier.wosquality | Q2 | en_US |
dc.indekslendigikaynak | Web of Science | en_US |
dc.language.iso | en | en_US |
dc.publisher | MATHEMATICAL SOC REP CHINA | en_US |
dc.relation.ispartof | TAIWANESE JOURNAL OF MATHEMATICS | en_US |
dc.relation.publicationcategory | Makale - Uluslararası Hakemli Dergi - Kurum Öğretim Elemanı | en_US |
dc.rights | info:eu-repo/semantics/closedAccess | en_US |
dc.selcuk | 20240510_oaig | en_US |
dc.subject | difference equation | en_US |
dc.subject | period 5k+10 solution | en_US |
dc.title | On the recursive sequence x(n+1) = xn-(5k+9)/1+xn-4xn-9 ... xn-(5k+4) | en_US |
dc.type | Article | en_US |